Greetings ...

I have to calculate the 2 formulas on both the attachments on the Square root of the Standard Deviation in PROIV.Your help will be greatly appreciated.

Matthews Estrice

Hi Matthews

The square root is found by raising the number to the power of .5 - for example

#square-root = #number**.5

What are you trying to calculate? I may have a global logic to do this!

Regards

Steve

Hi Steve,

I am trying to work out the :-

1) The Population Standard Deviation
σ = √(8.9) = 2.983...  (as per the example on the link)

2) The Sample Standard Deviation
s = √(13.1) = 3.619...  (as per the example on the link)

from the ff. link :- http://www.mathsisfu...n-formulas.html  .Please use the provided same data to test your PROIV global logic.

Once we have a PROIV logic that can solves the 2 examples to obtain the above answers ,we can then substitute the values in the link above with our values using the same formulas to see if we derive to the same answers.

Thansk and regards,

Matthews

Hi Steve,

I am trying to work out the :-

 

1) The Population Standard Deviation
σ = √(8.9) = 2.983...  (as per the example on the link)

 

2) The Sample Standard Deviation
s = √(13.1) = 3.619...  (as per the example on the link)

 

from the ff. link :- http://www.mathsisfu...n-formulas.html  .Please use the provided same data to test your PROIV global logic.

 

Once we have a PROIV logic that can solves the 2 examples to obtain the above answers ,we can then substitute the values in the link above with our values using the same formulas to see if we derive to the same answers.

 

Thansk and regards,

Matthews

 So the logic will be #S = #VARIABLE**.5 and in this case an answer of 3.619392 to 6 decimal places - works fine

Thank you so much for the answer Steve.