For all you bored mathematicians out there...

Let us say I have a supply of mixed fluid. The mix is 35% Fluid A, and 65% H2O. I also have supplies of 100% Fluid A.

What formula do I need, to calculate how much 100% Fluid A, to add to my mixed fluid, such that I now have a 50% Fluid A, 50% H2O mix in any size vessel - and I'm maximising my use of the 35%/65% mix?

Assuming you think of it from a programming perspective - the only screen prompt would be for size of vessel.

Example: I have a 250 US Gal (appox 945L) container. How much each of 35%/65% and 100% do I need?

Cheers

Rick

# Math

Started by Rick Young, Sep 01 2006 06:45 PM

2 replies to this topic

### #2

Posted 01 September 2006 - 07:19 PM

From my chemistry days:

You need V/(2*.65) of the mixed solution and V - (V/(2*.65) of the pure solution.

For example, with a 250 US Gallon container, you need 250/1.3 = 192.31 gallaons of the mixed solution, and (250 - 192.31) = 57.69 gallons of the pure solution.

Explanation:

You want to end up with 125 gallons of H2O and 125 of Fluid A. The only way to do this is to put enough from the mixed solution to give you 125 gallons of H2O (192.31 * .65). The balance in the container must come from the pure solution, (250 - 192.31).

You need V/(2*.65) of the mixed solution and V - (V/(2*.65) of the pure solution.

For example, with a 250 US Gallon container, you need 250/1.3 = 192.31 gallaons of the mixed solution, and (250 - 192.31) = 57.69 gallons of the pure solution.

Explanation:

You want to end up with 125 gallons of H2O and 125 of Fluid A. The only way to do this is to put enough from the mixed solution to give you 125 gallons of H2O (192.31 * .65). The balance in the container must come from the pure solution, (250 - 192.31).

# Reply to this topic

#### 0 user(s) are reading this topic

0 members, 0 guests, 0 anonymous users